Thursday, 17 December 2015

Quantitative Aptitude Shortcuts : Problem on Ages

IBPS BANK EXAM PO AND CLERK : Quantitative Aptitude - Problem on Ages (Concepts)

Quantitative Aptitude Tricks for IBPS PO and Clerk Exam

In a series of providing free resources for preparation of IBPS PO, Clerk, Specialist officers, SBI PO, SBI clerk and other government jobs exams. We have started Quantitative Aptitude preparation series. We will try to cover every topic of Quantitative section, please ask your in comments section, In case you are finding any kind of difficulty in any chapter just leave a reply. We will try to write a post on that topic as soon as possible.


Read given below questions and understand the method of solving. It will help you how to solve age related questions in IBPS Bank PO and Clerk as well as all Banking Exams.
 
Basic Formula:

If the present age of A is ‘x’ years, the age of A, n years ago was (x-n) years, and the age of a after n years will be (x+n) years.

Trick 1. Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of Rajeev ?
 
Sol. Let Rajeev's present age be x years. Then,
Rajeev's age after 15 years = (x + 15) years.
Rajeev's age 5 years back = (x - 5) years.
Therefore x + 15 = 5 (x - 5)
x + 15 = 5x - 25
4x = 40
x = 10.
Hence, Rajeev's present age = 10 years.


Trick 2. The ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old as the younger one, find their present ages.
 
Sol. Let the age of the younger person be x years.
Then, age of the elder person = (x + 16) years.
Therefore 3 (x - 6) = (x + 16 - 6)
3x -18 = x + 10
2x = 28
x = 14.
Hence, their present ages are 14 years and 30 years.


Trick 3. The product of the ages of Ankit and Nikita is 240. If twice the age of Nikita is more than Ankit's age by 4 years, what is Nikita's age?
 
Sol. Let Ankit's age be x years. Then, Nikita's age = 240/x years.
2 * (240 /x ) – x = 4
480 – x2 = 4x
x2 + 4x – 480 = 0
( x+24)(x-20) = 0
x = 20.
Hence, Nikita's age = 240/x = 240/20 years = 12 years.


Trick 4. The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. Find the present age of the father.
 
Sol. Let the son's present age be x years. Then, father's present age = (3x + 3) years
(3x + 3 + 3) = 2 (x + 3) + 10
3x + 6 = 2x + 16
x = 10.
Hence, father's present age = (3x + 3) = ((3 * 10) + 3) years = 33 years.


Trick 5. Rohit was 4 times as old as his son 8 years ago. After 8 years, Rohit will be twice as old as his son. What are their present ages?
 
Sol. Let son's age 8 years ago be x years. Then, Rohit's age 8 years ago = 4x years.
Son's age after 8 years = (x + 8) + 8 = (x + 16) years.
Rohit's age after 8 years = (4x + 8) + 8 = (4x+ 16) years.
2 (x + 16) = 4x + 16
2x = 16 => x = 8.
Hence, son's 'present age = (x + 8) = 16 years.
Rohit's present age = (4x + 8) = 40 years.


Trick 6. One year ago, the ratio of Gaurav's and Sachin's age was 6: 7 respectively. Four years hence, this ratio would become 7: 8. How old is Sa chin ?
 
Sol. Let Gaurav's and Sachin's ages one year ago be 6x and 7x years respectively.
Then, Gaurav's age 4 years hence = (6x + 1) + 4 = (6x + 5) years.
Sachin's age 4 years hence = (7x + 1) + 4 = (7x + 5) years.
(6x+5): (7x + 5) = 7:8
8(6x+5) = 7 (7x + 5)
48x + 40 = 49x + 35
x = 5.
Hence, Sachin's present age = (7x + 1) = 36 years.


Trick 7. The Ratio of Ages of Mona and Sona is 4:5. Twelve Years hence, their ages will be in the ratio of 5:6. What will be Sona's age after 6 years ?
 
Sol. Let their present ages be 4x & 6x
Then (4x + 12)/(5x + 12) = 5/6 or x=12
Sona's age after 6 years = (5x +6) = 66 years


Trick 8. Ramu was 4 times as old as his son 8 years ago. After 8 years, Ramu will be twice as old as his son. What their present ages ?
 
Sol. Let son's age 8 years ago be x years
Then Ramu's age at that time = 4x years
Son's age after 8 years = (x +8) + 8 = (x + 16) years
Ramu's age after 8 years = (4x + 8) + 8 = (4x + 16) years
2(x + 16) = 4x + 16 or x=8
Son's present age = (x + 8) = 16 years
Ramu's present age= (4x + 8) = 40 years


Trick 9. A man is four times as old as his son. Five years ago, the man was nine times as old his son was at that time. What is the present age of a man ?
 
Sol. Let son's age = x, then man's age =4x.
9(x - 5) = (4x-5) or x=8.
Man's present age = (4x + 7) = 35 years


Trick 10. The sum of ages of Aruna and her mother is 49 years. Also, 7 years ago, the mothers age was 4 times Aruna's age. Find the present age of Aruna's mother.
 
Sol. Let Aruna's age 7 years ago be x.
Mother's age 7 years ago = 4x
(x + 7) + (4x + 7) =49 or x=7
Mother's present age = (4x + 7) = 35 years


Trick 11. The ages of A and B differ by 16 years. If 6 years ago, the elder one be 3 times as old as the younger one, find their present ages.
 
Sol. Let A's age = x & B's age = (x + 16)
3(x - 6) = (x + 16 - 6) or x=14
A's age = 14 years & B's age = 30 years.


Read IBPS Quantitative Aptitude TricksNumerical Ability Guide Series:

1 comment:

  1. Thanks for providing problems on ages. It was really amazing. Can you please provide more questions related to same topic?
    with regards
    Bank Exam Coaching Centres in Chennai

    ReplyDelete

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